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Use the window design method to design a multiband filter that meets the following specifications:

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On the fourth iteration, shown in Figure 15.26, the highest priority vertex among those still in the priority queue is x = B with distance field 4. Steps 7 10 iterate twice, for y = C and E. The values of s computed for these are 4 + 3 = 7 and 4 + 5 = 9. The second of these is less than the current (infinite) value at E, so its distance field assigned the value 9 and its back pointer is set to B. But the s value 7 is not less than the current distance field for C, so its fields do not change. The algorithm progresses through its remaining iterations, shown in Figure 15.27, for x = C, E, G, and finally H the same way.

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To design a multiband filter that meets these specifications usmg the window design method, we begin by finding the ideal unit sample response. For the frequency response of the ideal filter. we set the cutoff frequencies equal to the midpoint of the transition bands. Therefore, we have

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22

The unit sample response of this ideal lilter may be found easily by noting that Hd(ei")may be written as an allpass plus a low-pass filter with a gain of 0.5 minus a low-pass ti lter with a gain of 0.5 and a cutoff frequency w, = 0 . 5 7 5 ~ filter with a gain of I and a cutoff frequency of w2 = 0.325n. Therefore. if we assume that H,,(eJW) linear phase has with a delay of n d ,

CHAP. 15]

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Having found the ideal unit sample response. the next step is to choose an appropriate window. When h d ( n ) is with multiplied by a window w(rr),the frequency response is the convolution of the transform of the window W ( e J W ) Hd(el'").Assuming that the length of the filter is long compared to the inverse of the transition width, so that the discontinuities between the bands may be treated independently. the ripples in the three bands will be approximately the same as they would be for a low-pass filter, except that they will be scaled by the amplitude of the discontinuities at the band edge. Therefore. if the ripple in the lower passband and the stopband are 4, the ripple in the upper passband will be 6 , , / 2 . Consequently. we must use a window that would produce a low-pass filter with a ripple no larger than 0.01. Thus. we may use a Hanning window. Finally, to determine the filter order, note that because the widths of both transition bands are the same. Ao) = 0 . 0 5 ~an. estimate of the filter order is ~

public class TestBinarySearch { public static void main(String[] args) { int[] a = {22, 33, 44, 55, 66, 77, 88, 99}; ch02.ex02.DuplicatingArrays.print(a); System.out.println("search(a, 44): " + search(a, 44)); System.out.println("search(a, 50): " + search(a, 50)); System.out.println("search(a, 77): " + search(a, 77)); System.out.println("search(a, 100): " + search(a, 100)); } public static int search(int[] a, int x) { // POSTCONDITIONS: returns an integer i; // if i >= 0, then a[i] == x; for (int i=0; i<a.length; i++) { // INVARIANT: x is not among a[0]...a[i-1] if (a[i] == x) { return i; } } return -1; } }

Note that another way to design this tilter would have been to design a network of three filters in parallel: a low-pass filter, a bandpass filter, and a high-pass filter. This approach would give greater control over the ripple amplitudes and the transition widths but would require a trial and error approach to establish the specifications for the three filters.

The final result is shown in Figure 15.28. It shows, for example, that the shortest path from A to E is ADFCE with length 6.

Shown in the following figure is the magnitude of the frequency response of a type I high-pass filter that was designed using the Parks-McClellan algorithm.

Table 15.1 shows a trace of Algorithm 15.2 on the graph shown in Figure 15.29. The start vertex is v0 = A.

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