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The next two iterations are shown in Figure 15.25. On the third iteration, the highest priority vertex among those still in the priority queue is x = F with distance field 3. Steps 7 10 iterate three times again, once for each of F s unvisited neighbors y = C, G, and H. The values of s computed for these are 3 + 1 = 4, 3 + 3 = 6, and 3 + 5 = 8. Each of these is less than the current value, so all of them are assigned and the back pointers are set to F. Note how this changes the distance field and pointer in vertex C again.

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With 6, = 0.002,

CHAP. 15]

and we have = 0.1 102(0r, - 8.7) = 4.99 The window length, N , on the other hand, is determined by the stopband ripple, 6,. and the transition width as follows:

Java includes a special utility class for processing arrays. The name of this class is Arrays, and it is defined in the java.util package. EXAMPLE 2.3 Using the java.util.Arrays Class

Consider the following specifications for a bandpass filter:

1. 2. 3. 4. 5. 6. 7. 8. 9.

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(a) For this filter, the width of each transition band is Aw = 0 . 1 ~ The ripples in the lower stopband, passband, . and upper stopband are 4 = 0.01. a2 = 0.05, and a3 = 0.02, respectively, and are all different. Because the ripples produced with the window design method will be approximately the same in all three bands, the filter must be designed so that it has a maximum ripple of 8, = 0.01 in all three bands. With

This program imports the Arrays class from the java.util package to access the sort(), binarySearch(), fill(), and equals() methods. It also imports the static print() method from Example 2.2.

i t follows that the Blackman window will satisfy this requirement. An estimate of the filter order necessary to meet the transition bandwidth requirement of A f = 0.05 with a Blackman window is

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Initialize an empty queue Q for temporary storage of vertices. Enqueue v0 into Q. Repeat steps 4 6 while Q is not empty. Dequeue Q into x. Add x to L. Do step 7 for each vertex y that is adjacent to x. If y has not been visited, do steps 8 9. Add the edge xy to T. Enqueue y into Q.

where Hd(eIW)is the frequency response of an ideal bandpass filter. For the cutoff frequencies of ~,,(ej"), we choose the midpoints of the transition bands of H ( e l ' " ) .Therefore.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

However, we want to delay this filter so that it is centered at N / 2 = 55. Therefore, the unit sample response of the tilter that is to be windowed should be

THE java.util.Arrays CLASS Java includes a special utility class for processing arrays. The name of this class is Arrays, and it is defined in the java.util package. EXAMPLE 2.3 Using the java.util.Arrays Class

Therefore, we set N = 45. Next, for the Kaiser window parameter, with an attenuation of 40 dB, we have

import java.util.Arrays; public class TestArrays { public static void main(String[] args) { int[] a = {44, 77, 55, 22, 99, 88, 33, 66}; print(a); Arrays.sort(a); print(a); int k = Arrays.binarySearch(a, 44); System.out.printf("Arrays.binarySearch(a, 44): %d%n", k); System.out.printf("a[%d]: %d%n", k, a[k]); k = Arrays.binarySearch(a, 45); System.out.printf("Arrays.binarySearch(a, 45): %d%n", k); int[] b = new int[8]; print(b); Arrays.fill(b, 55); print(b); System.out.println("Arrays.equals(a,b): " + Arrays.equals(a,b)); } }

h(n) = w(n).hd(n)

This program imports the Arrays class from the java.util package to access the sort(), binarySearch(), fill(), and equals() methods. It also imports the static print() method from Example 2.2.

44 77 55 22 99 88 33 66 22 33 44 55 66 77 88 99 Arrays.binarySearch(a, 44): 2 a[2]: 44 Arrays.binarySearch(a, 45): -4 0 0 0 0 0 0 0 0 55 55 55 55 55 55 55 55 Arrays.equals(a,b): false The array a[] is created and printed at lines 5 6. At line 7, the call Arrays.sort(a) sorts the elements

Suppose that we would like to design a bandstop filter to meet the following specifications:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

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