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The algorithm that we use in this example is find_if Its first two arguments are iterators that denote a sequence; the third is a predicate, which tests its argument and returns true or false The find_if function calls the predicate on each element in the sequence, stopping when it finds an element for which the predicate yields true The standard library provides an isspace function to test whether a character is a space However, that function is overloaded, so that it will work with languages, such as Japanese, that use other character types, such as wchar_t ( 13/14) It's not easy to pass an overloaded function directly as an argument to a template function The trouble is that the compiler doesn't know which version of the overloaded function we mean, because we haven't supplied any arguments that the compiler might use to select a version Accordingly, we'll write our own predicates, called space and not_space, that make clear which version of isspace we intend The first call to find_if seeks the first nonspace character, which begins a word Remember that one or more spaces might begin a line or might separate adjacent words in the input We don't want to include these spaces in the output After the first call to find_if, i will denote the first nonspace, if any, in str We use i in the next call to find_if, which looks for the first space in [i, strend()) If find_if fails to find a value that satisfies the predicate, it returns its second argument, which, in this case, is strend() Therefore, j will be initialized to denote the blank that separates the next word in str from the rest of the line, or, if we are on the last word in the line, j will be equal to strend() At this point, i and j delimit a word in str All that's left is to use these iterators to copy the data from str into ret In the earlier version of split, we used string::substr to create the copy However, that version of split operated on indices, not iterators, and there isn't a version of substr that operates on iterators Instead, we construct a new string directly from the iterators that we have We do so by using an expression, string(i, j), that is somewhat similar to the definition of spaces that we explained in 12/13 Our present example constructs a string that is a copy of the characters in the range [i, j) We push this new string onto the back of ret It is worth pointing out that this version of the program omits the tests of the index i against strsize() Nor are there the obvious equivalent tests of the iterator against strend() The reason is that the library algorithms are written to handle gracefully calls that pass an empty range For example, at some point the first call to find_if will set i to the value returned by strend(), but there is no need to check i before passing it to the second call to find_if The reason is that find_if will look in the empty range [i, strend()) and will return strend() to indicate that there is no match.

The updateTreeFromTextEditor() method has already been defined (see Section 823, Editor model, on page 363), but the updateTextEditorFromTree() method has not, so add it now

void updateTextEditorFromTree() { textEditor getDocumentProvider() getDocument(textEditorgetEditorInput()) set(((PropertyFile) treeViewergetInput())asText()); }

Classes containing methods or constructors whose invocation indicates a transfer of control cannot defend themselves against malicious clients Such classes are acceptable only when there is mutual trust between the class and its client or when damage to the class's invariants would harm no one but the client An example of the latter situation is the wrapper class pattern (Item 14) Depending on the nature of the wrapper class, the client could destroy the class's invariants by directly accessing an object after it has been wrapped, but this typically would harm only the client

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Another character-manipulation problem that we can use the library to solve succinctly is determining whether a word is a palindrome Palindromes are words that are spelled the same way front to back as back to front For example, "civic," "eye," "level," "madam," and "rotor" are all palindromes Here is a compact solution that uses the library:

The updateTextEditorFromTree() method calls a new asText() method in the PropertyFile The new asText() method reverses the parsing process in the PropertyFile s constructor (see Section 823, Editor model, on page 363) by reassembling the model into a textual representation

public String asText() { StringWriter stringWriter = new StringWriter(2000); PrintWriter writer = new PrintWriter(stringWriter); unnamedCategoryappendText(writer); Iterator<PropertyCategory> iter = categoriesiterator(); while (iterhasNext()) { writerprintln(); iternext()appendText(writer); } return stringWritertoString(); }

bool is_palindrome(const string& s) { return equal(sbegin(), send(), srbegin()); }

The asText() method calls a new appendText(PrintWriter) method in PropertyCategory:

The return statement in this function's body calls the equal function and the rbegin member function, both of which we have not yet seen Like begin, rbegin returns an iterator, but this time it is an iterator that starts with the last element in the container and marches backward through the container The equal function compares two sequences to determine whether they contain equal values As usual, the first two iterators passed to equal specify the first sequence The third argument is the starting point for the second sequence

public void appendText(PrintWriter writer) { if (namelength() > 0) { writerprint("# "); writerprintln(name); } Iterator<PropertyEntry> iter = entriesiterator(); while (iterhasNext()) iternext()appendText(writer); }

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which then calls a new appendText(PrintWriter) method in PropertyEntry:

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public void appendText(PrintWriter writer) { writerprint(key); writerprint(" = "); writerprintln(value); }

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