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WHEN YOU SEE AN AC CIRCUIT THAT CONTAINS COILS AND/OR CAPACITORS, YOU SHOULD ENVISION a complex-number plane, either RX (resistance-reactance) or GB (conductance-admittance). The RX plane applies to series circuit analysis. The GB plane applies to parallel circuit analysis.

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Optical networking is often viewed as a point-to-point technology. It has achieved such a position of prominence in the last two years, however, that it qualifies as a transport option in its own right. Furthermore, optical switching is fast becoming real and optical routing is not far behind. In this next section, we discuss the development of optical networking, the various technologies that it employs, and the direction it seems to be going in this fast-paced market.

Find the absolute value of 0 j34. This is a pure imaginary number. The value of b in this case is 0 j( 34). Therefore, the absolute value is ( 34) 34. 34, because 0 j34

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When you see resistors, coils, and capacitors in series, each component has an impedance that can be represented as a vector in the RX plane. The vectors for resistors are constant, regardless of the frequency. But the vectors for coils and capacitors vary with frequency.

Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

Problem 15-3

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Pure Reactances Pure inductive reactances (X L ) and capacitive reactances (X C ) simply add together when coils and capacitors are in series. Thus, X = X L + X C. In the RX plane, their vectors add, but because these vectors point in exactly opposite directions inductive reactance upward and capacitive reactance downward (Fig. 16-1) the resultant sum vector inevitably points either straight up or straight down, unless the reactances are equal and opposite, in which case they cancel and the result is the zero vector. Problem 16-1 Suppose a coil and capacitor are connected in series, with jX L = j200 and jX C = j150. What is the net reactance Just add the values: jX = jX L + jX C = j200 + ( j150) = j(200 150) = j50. This is a pure inductive reactance, because it is positive imaginary. Problem 16-2 Suppose a coil and capacitor are connected in series, with jXL = j30 and jX C = j110. What is the net reactance

Find the absolute value of 3 j4. In this number, a 3 and b 4, because 3 j4 can be rewritten as 3 j( 4). Squaring both of these, and adding the results, gives 32 ( 4)2 9 16 25. The square root of 25 is 5; therefore, the absolute value of this complex number is 5. You might notice this 3, 4, 5 relationship and recall the Pythagorean theorem for finding the length of the hypotenuse of a right triangle. The formula for finding the length of a vector in the complex-number plane comes directly from this theorem. If you don t remember the Pythagorean theorem, don t worry; just remember the formula for the length of a vector.

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