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the basic power control loop functions in Release 99 are just as essential for HSUPA operation. HSUPA provides a exible path beyond the 384-kbps uplink which can be seen as the realistic maximum for WCDMA before HSUPA. A similar technology to that of HSDPA is being used by introducing fast uplink hybrid-ARQ (HARQ), Node B based uplink scheduling (as shown in Figure 5.1) and easier multicode transmission than with Release 99. The focus in this chapter is on the additions to the Release 6 speci cations that the HSUPA feature entails, and the functionality of the Release 99 uplink is described as a reference in the most relevant cases. Anyway, it is worth keeping in mind that none of the old features were replaced by HSUPA and that it was more of an add-on than a replacement. The complete description of all the features needed for, say, synchronization and cell search can be found in [1].

, am ) i 0; a0 0; repeat i i + 1; x ai 1 + 1; while C(m i, n x) rank do {rank rank C(m i, n x); x x + 1}; ai x until rank = 0; for j = i + 1 to m do aj n m + j What is 104th (4,9)-combination There are C(3, 8) = 56 (4,9)-combinations starting with a 1 followed by C(3, 7) = 35 starting with 2 and C(3, 6) = 20 starting with 3 Since 56 + 35 104 but 56 + 35 + 20 > 104 the requested combination begins with a 3, and the problem is reduced to nding 104 56 35 = 13th (3,6)-combination There are C(2, 5) = 10 combinations starting with 34 and C(2, 4) = 6 starting with a 5.

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O f f i c e r s a n d D i r e c t o r s B e w a r e Yo u C a n B e L i a b l e for Mismanaging Intellectual Proper ty

Since 13 > 10 but 13 < 10 + 6 the second element in combination is 5, and we need to nd 13 10 = 3rd (2,4)-combination out of {6, 7, 8, 9}, which is 78, resulting in combination 3578 as the 104th (4,9)-combination We also consider the ranking of subsets The subsets in the set and in the binary representation are listed in different lexicographic orders In binary representation, the ranking corresponds to nding decimal equivalent of an integer in binary system Therefore the rank of a subset b1 , b2 , , bn is bn + 2bn 1 + 4bn 2 + + 2n 1 b1 For example, the rank of 100101 is 1 + 4 + 32 = 37 The ranks are here between 0 and 2n 1 since in many applications empty subset (here with rank 0) is not taken into consideration.

might have either a sharable or nonsharable problem, depending on how he perceives it Cressey then divided nonsharable problems into six subcategories:3 1 Violation of ascribed obligations Simply put, this is the accumulation of debts, legitimate or otherwise, that the individual believes are incompatible with their social role(s) as husband, father, employee, friend, and so on, and, therefore, cannot be shared without embarrassment or loss of social standing 2 Personal failure While some issues in this category might be macroeconomic in nature (eg, a recession), others are microeconomic and more intensely personal (eg, poor investment decisions) 3 Business reversals While similar to the personal failure category, Cressey here saw patterns of people willing to violate trusts to try to save a dying business 4 Physical isolation Some persons, faced with financial pressures, simply have, or perceive that they have, no one to turn to for help.

The ranking functions can be generalized to variations out of {0, 1, , m 1} by simply replacing all 2 by m in the rank expression It corresponds to decimal equivalent of a corresponding number in number system with base m..

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